2/5(x^2+1)=x

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Solution for 2/5(x^2+1)=x equation: 


x in (-oo:+oo)

(2/5)*(x^2+1) = x // - x

(2/5)*(x^2+1)-x = 0

2/5*(x^2+1)-x = 0

2/5*(x^2+1)-x = 0

2/5*x^2-x+2/5 = 0

2/5*x^2-x+2/5 = 0

2/5*x^2-x+2/5 = 0

DELTA = (-1)^2-(2/5*2/5*4)

DELTA = 9/25

DELTA > 0

x = ((9/25)^(1/2)+1)/(2/5*2) or x = (1-(9/25)^(1/2))/(2/5*2)

x = 2 or x = 1/2

(x-1/2)*(x-2) = 0

(x-1/2)*(x-2) = 0

( x-1/2 )

x-1/2 = 0 // + 1/2

x = 1/2

( x-2 )

x-2 = 0 // + 2

x = 2

x in { 1/2, 2 }

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